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Powershell Positional Parameters Cannot Be Found


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The first is Class, the second one is Credential, and the last parameter is ComputerName. This value must be enclosed in single quotes. Is the target or the destination the first parameter? Either way, you need to pass a single argument to the -Path parameter of Test-Path: PowershellInvoke-Command -ComputerName $Computer -ScriptBlock { test-path -Path ('d:\MININT' + '\' $env:computername´╗┐) } So on a computer weblink

A Positional Parameter Cannot Be Found That Accepts Argument 'true'

However, there are a few caveats. If you assign a string value (like a folder name) to a variable you always have to enclose that value in double quotes (or single quotes; that’ll work, too). Why are wavelengths shorter than visible light neglected by new telescopes? Instructions on how to proceed from here?

I'd like to create a for loop and simply iterate over both arrays to complete the transfer of files/folders from staging to dev server. C# TBB updating metadata value As a monk, can I use Deflect Missiles to intentionally catch a projectile? Reply mredwilson says: November 10, 2016 at 4:09 am @BigTeddy please email me at [email protected] your name was drawn in the random prize drawings but your email bounces back. A Positional Parameter Cannot Be Found That Accepts Argument False This is not a compatibility issue because we do not guarantee that partial parameter names will ever work.

Can a text in Latin be understood by an educated Italian who never had any formal teaching of that language? have a look at this for env variables http://blogs.technet.com/b/heyscriptingguy/archive/2010/03/14/hey-scripting-guy-march-14-2010.aspx 0 Thai Pepper OP mattmcnabb Mar 25, 2015 at 11:13 UTC The problem is this line: Powershelltest-path d:\MININT +´╗┐ If I decide not to use the loop, the error goes away and the files transfer properly. http://stackoverflow.com/questions/28374419/a-positional-parameter-cannot-be-found-that-accepts-argument PS C:> gwmi win32_bios -co localhost SMBIOSBIOSVersion : 8BET47WW (1.27 ) Manufacturer : LENOVO Name : Default System BIOS SerialNumber : R9FPY3P Version : LENOVO – 1270 Consider the following issues

Instead, PowerShell sees a string value enclosed in a pair of single quote marks; consequently, PowerShell thinks this this is a separate parameter value. Import-module A Positional Parameter Cannot Be Found That Accepts Argument The way most people learn about parameter aliases is by looking at the code from someone who has learned about the parameter alias from someone else. Some PowerShell cmdlets allow you to enter multiple values for a single parameter. Well, here’s why.

A Positional Parameter Cannot Be Found That Accepts Argument Exchange 2010

What do I do? https://blogs.technet.microsoft.com/csps/2010/09/12/when-do-i-have-to-put-double-quotes-around-parameter-values/ How to delete the lines from a file that do not contain dot? A Positional Parameter Cannot Be Found That Accepts Argument 'true' I had a powershell script that I wanted to extend with similar behavior. A Positional Parameter Cannot Be Found That Accepts Argument Copy Item On which point(s) in a jet engine does the reaction force act?

Well, let’s find out. check over here The line below works and starts up the Greenshot exe file (but ofcourse isn't silent), so I think installing from UNC path is not the problem: Start-Process -Credential ($credentials) -FilePath "\\server1\msi\New_Machine\$Greenshot" How do I make an alien technology feel alien? Join them; it only takes a minute: Sign up A positional parameter cannot be found that accepts argument '\*' up vote 0 down vote favorite I have a number of web A Positional Parameter Cannot Be Found That Accepts Argument 'binpath='

Inside that directory I have my skeleton directory that I put the basis of my projects into. PS C:> gwmi win32_bios localhost Get-WmiObject : Invalid query At line:1 char:5 + gwmi <<<< win32_bios localhost + CategoryInfo : InvalidOperation: (:) [Get-WmiObject], ManagementExce ption + FullyQualifiedErrorId : That explains why using a parameter value like Redmond,WA fails, at least when using the Get-CsVoicePolicy cmdlet. his comment is here mkdir: A positional parameter cannot be found that accepts argument 'docs'.

Try these: "$($stagingArray[$i])\*" Surrounding it in quotes makes it evaluate the whole thing as a string. $($stagingArray[$i]) + '\*' This will concatenate the result of the sub-expression and the string containing Start-process A Positional Parameter Cannot Be Found That Accepts Argument Now, this is a lot of typing. For example, there could be partial parameter conflicts in other cmdlets that would necessitate using Com or even Comp.

For example, this command returns the voice policy RedmondVoicePolicy: Get-CsVoicePolicy "RedmondVoicePolicy" So does this command: Get-CsVoicePolicy ‘RedmondVoicePolicy' And so does this one: Get-CsVoicePolicy RedmondVoicePolicy In

Why were pre-election polls and forecast models so wrong about Donald Trump? PS C:> gwmi win32_bios -c localhost Get-WmiObject : Parameter cannot be processed because the parameter name ‘c' is ambi guous. This allows you to call a cmdlet without specifying the parameter name. A Positional Parameter Cannot Be Found That Accepts Argument Deletecontent Windows PowerShell scripting techniques PowerTip guest blogger VBScript getting started Weekend Scripter Sean Kearney Office Active Directory operating system storage WMI files text files community desktop management 2011 Scripting Games 2012

For that matter, what is the copy command? Browse other questions tagged powershell or ask your own question. How to stop NPCs from picking up dropped items GO OUT AND VOTE River Crossing Puzzle How do pilots identify the taxi path to the runway? weblink The big problem with positional parameters comes into play where a cmdlet positionally accepts multiple parameters.

Creating your account only takes a few minutes. Again, however, no such item can be found; all PowerShell sees is the value Voice. The second parameter is destination. Do I need to quote the sub-expression? –NealR Feb 6 '15 at 20:50 Nevermind, enclosing the variables/string in parenthesis solved the problem: ($($stagingArray[$i]) + '\*') –NealR Feb 6 '15

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